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变音门铃如何设计？

变音门铃如何设计？

浏览：27次 | 提问时间： 07-29 08:08

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蔓栀 07-29 08:09

你说的*门铃是属于多音门铃类，IC便是时基电路集成块555，它构成无稳态多谐振荡器。按下按钮AN（装在门上），振荡器振荡，振荡频率约700Hz，扬声器发出“叮”的声音。与此同时，电源通过二极管D1给C1充电。放开按钮时，C1便通过电阻R1放电，维持振荡。但由于AN的断开，电阻R2被串入电路，使振荡频率有所改变，大约为500Hz左右，扬声器发出“咚”的声音。直到C1上电压放到不能维持555振荡为止。“咚”声的余音的长短可通过改变C1的数值来改变

那把破扇▽当济公 07-29 08:17

*门铃的制作R1电阻30K20R2电阻22K20R3电阻22K20R4电阻47K20C1电解电容器10/F10V20C2涤纶电容器0.033F20C3电解电容器47/F10V20VD1二极管IN414820VD2二极管IN414820IC集成电路NE55520

无梦为安 07-29 08:25

门铃电路简易*门铃：当有人按门铃的时候它响的时间一般比简单的叮咚长些，还有就是不让人感觉枯燥乏味。总之，音乐门铃的作用就是让里面的人可以边听歌边开门咯。一：工作原理简易*门铃电路如图所示。R1120kR251kR31kC122uC222uE3VVT1VT2BAN(A)*门铃电路图中，三极管VT1、VT2组成互补式自激多谐震荡电路。所谓*门铃是指电路的震荡频率不仅取决于（R1+R2）.C2的时间常数，还取决于电容C1两端的冲放电压高低。当按钮开关AN未接通时，三极管VT1的基极电流为零，VT1、VT2组成的低频震荡电路不工作，电路基本上不耗电。当按下按钮开关AN时，电源经电阻R1向电容C1充电，待C1的电压上升至三极管VT1、VT2组成的震荡电路起振，扬声器B开始发声。随着电容C1两端电压继续上升，振荡频率随之逐渐增高。待C1上两端电压接近电源电压时，振荡频率不再变化而趋于稳定。当松开按钮开关AN后，电容C1经电阻R2和VT1的发射结放电，随着C1上的电压逐渐下降，电路振荡频率随之降低，声音也逐渐减小。当电容C1两端电压降至VT1基极工作电压以下时，VT1、VT2组成的振荡电路停振，扬声器B无声音发出。二：元器件介绍电阻器：它具有分压和限流功能，用符号表示，此设计中采用金属膜电阻器，由于它的耐热性，稳定性好于其它电阻器，且体积远小于同类功率的其它电阻器，因此可适用于稳定性和可靠性要求较高的场合。电容器：它是一种贮存电能的元件，它通交流，隔直流。通高频，阻低频。用符号表示。此设计中采用电解电容和有机薄膜电容器两种；有机薄膜电容器由聚*乙*等有机材料代替纸介，它体积小，耐高压，损耗小，绝缘电阻小，稳定性好，但温度系数较大，适用于高压电路，谐振回路，滤波电路中。电解电容器：其长脚为正极，短脚为负极，在电容器表面印有负极标记。电解电容在使用中禁止极性接反，若接反，其内部电流过大，导致其过热击穿，它容量大，在短时间内过压击穿后，能自动修补，适用于在整流电路中进行滤波，电源去耦，放大器中的耦合和旁路等。二极管：半导体二极管：半导体导电能力介于导体和绝缘体之间。二极管按材料不同可分为硅管和锗管。此设计中用到稳压二极管，发光二极管。稳压二极管：是用特种工艺*的面结型硅半导体二极管，其特点工作于反向击穿区，实现稳压，其被反向击穿后，当外加电压减小或消失，PN结能自动恢复，而不至于损坏，稳压管主要用于电路的稳压环节和直流电源电路中。发光二极管：简称LED。当有额定电流通过它时，便会发出一定颜色的光，LED可用直流，交流，脉冲等电源驱动。但必须串联限流电阻，它把电能转换成光能，广泛应用于音响设备，数控装置等设备的显示器上。三：元件选择VT1:NPN型三极管，可选用3DG6或9014、9013型等。VT2:PNP型三极管，可选用3AX31、CG23或9012型等。R1-R3:选用1/8W金属膜或碳膜电阻。C1:选用耐压10V电解电容。C2:选用瓷介或玻璃釉电容。AN:选用小型电铃按钮开关。B:选用50mm、8欧姆、0.25W动圈式扬声器。E:选用2节5号电池串联。3、制作与调试电路组装正确无误，元器件又良好，且焊接牢固，一般接上电源按下按钮开关AN，扬声器立即能发出音调变化的声音。若感觉声音不清脆、悦耳，可改变电阻R3或电容C2的参数试验。门铃发声时间长短，根据自己需要调整电容C1的容量。按钮开关AN通过引线安装在门外，电路板、扬声器和电池固定安装在相应大小木盒或塑料盒内装在门内墙上。四：总结门铃电路制作总结：通过制作门铃电路，让我更加体会到：以往的教学都是教师事先准备好的，各个元器件都摆放在实验台上，甚至于先连接那一个元器件都有*来安排，出现了故障，就有*来解决，所谓的“动手动脑”都是有*安排解决的，应知部分的理论知识在内容上与技能严重脱节，*一点自主能力*没有，完成不能适应企业的各项要求，因而难以获得满意的教学效果。通过开展项目活动，能充分调动和发挥*参与教学活动的积极性和主观能动性，能使*的技能训练与知识学习、理解有机而有序的融合在一起，能使教学中的制作环境与过程贴进企业实际。这样就有利于培养*的自学自我管理能力，并根据生活生产的实际要求，设计一些更贴近*实际能力的内容和要求，以便于激发*的学习自觉性和对自身能力的认识以及肯定。作为一名*，有好多需要学习的地方，希望在以后的实际制作中发挥更好的水平

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