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家装电线用量怎么算

浏览：31次 | 提问时间： 08-04 10:51
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6个答案
ジ百媚妖嬈づ 08-04 10:52

100平米房屋面积家装例电线用量致参考：采用铜芯单股线（BV）或铜芯股软线（BVR）型号规格档装修高档装修1.5 3卷 4~5卷2.5 4卷 4~5卷4 1卷 2~3卷双色线 2卷 2~3卷采用铜芯护套线（BVVB-两芯护套线）型号规格档装修2×1.5 1卷2×2.5 2卷2×4 1卷双色线 2卷说明：100mm2房屋推荐用量实际用量要根据房屋面积及灯具、电器、插座、空调少作相应调整

你有多好呢 08-04 11:00

难说清楚,走线布局影响.全部放路主线省线,能要3圈.2.5,1.5,1.0各圈,2.5主线/插座,1.5照明/插座,1.0照明/线2.5能带21.5P挂机,别功率电器.线并联用要准确,先画线位置用尺量,再加15%工两三四百

我能和谁相拥 08-04 11:08

了解一些最基本的电工常识：一、常用电线种类的使用对象－－照明灯一般用1.5平方；插座用2.5平方的；大功率电器(空调、电热水器、小厨宝、集成灶、油烟机等）用4平方的电线。大功率电器一般也都会采用三孔插座（不是五孔下面的那种三孔，是单独的三孔）。二、电路基本知识－－并联时电压才能保证一致。也就是说每个照明灯或插座都要从总开关那里引出来。三，插座一般要三根线，照明灯需要两根线。这三点是计算电线用量的基础。确定各功能区的插座、照明灯及相关用电单元的数量和位置。比如照明灯的数量：餐厅1，客厅1，主卧1，次卧1，厨房1，阳台1，卫生间1共6个，再把每一个灯的位置到入户门附近的总开关位置的距离测量出来，零线火线各一根，也就是距离乘以2即是每一处照明灯所需的电线长度。例如客厅灯离总关的距离是6米，所需1.5平方的用线量就是6*2＝12米。（算插座时则*3）插座位置确*应该考虑的因素：一般来说有照明的地方就应该有插座，而且最好每个照明位置要考虑设置2个以上。主要功能区，比如厨房，卫生间等都要设3个以上。有电视，电器的地方不用说，最主要是要考虑*充电，电脑等不确定的因素。客厅一般还要考虑地插。注意特殊家用电器的用线。现在静水设备在很多地方已经普及，不论目前要不要安装，最好预留好净水器和饮水机的插座。还有就是*处理，音响等。

寻找远方 08-04 11:17

100平米房屋面积家装例电线用量致参考：采用铜芯单股线（BV）或铜芯股软线（BVR）型号规格档装修高档装修1.5 3卷 4~5卷2.5 4卷 4~5卷4 1卷 2~3卷双色线 2卷 2~3卷采用铜芯护套线（BVVB-两芯护套线）型号规格档装修2×1.5 1卷2×2.5 2卷2×4 1卷双色线 2卷说明：100mm2房屋推荐用量实际用量要根据房屋面积及灯具、电器、插座、空调少作相应调整

触摸不到的你 08-04 11:25

主线看功率用10或6平电线空调用4平,插座用2.5平,照明用1.5平,厨房插座全部4平确定走向距离先铺主线确定线盒位置数量功能距主线少米进行计算

紛紛擾擾我也不想管 08-04 11:34

1、首先，要确定门口到各个功能区(主卧室、次卧室、儿童房、客厅、餐厅、主卫、客卫、厨房、阳台、走廊)最远位置的距离。把上述距离量出来，有：A米、B米、C米、D米、E米、F米、G米、H米、I米、K米共11个结果 。2、然后确定各功能区灯的数量(各功能区同种辅灯统一算一盏)，各功能区插座数量，各功能区大功率电器数量(没有用0表示)。3、计算1.5MM电线长度为：(A+5米)乘主卧灯数；(B+5米)乘次卧灯数；(C+5米)乘儿卧灯数；(D+5米)乘客厅灯数； (E+5米)乘餐厅灯数； (F+5米)乘主卫灯数；(G+5米)乘客卫灯数；(H+5米)乘厨房灯数；(I+5米)乘阳台灯数；(K+5米)乘走廊灯数；上述结果之和乘于2。4、计算2.5MM电线长度为： (A+2米)乘主卧插座数；(A+2米)乘主卧插座数；(B+2米)乘次卧插座数；(C+2米)乘儿卧插座数；(D+2米)乘客厅插座数； (E+2米)乘餐厅插座数；(F+2米)乘主卫插座数；(G+2米)乘客卫插座数；(H+2米)乘厨房插座数；(I+2米)乘阳台插座数；(K+2米)乘走廊插座数；上数结果之和乘于3。5、4MM电线长度为：(A+4米)乘主卧大功率电器数量；(B+4米)乘次卧大功率电器数量；(C+4米)乘儿卧大功率电器数量；(D+4米)乘客厅大功率电器数量；(E+3米)乘餐厅大功率电器数量；(F+3米)乘主卫大功率电器数量；(G+3米)乘客卫大功率电器数量；(H+3米)乘厨房大功率电器数量；(I+2米)乘阳台大功率电器数量；(K+2米)乘走廊大功率电器数量；上述之和乘于3。6、3室2厅2卫1厨房1阳台的房子 以上A.B.C.D.E.F.G.H.I.J.K真实*为12米 12米 15米 7米 4米 12米 4米 6米 15米 0米 8米，如果各功能区灯的数量都为1，各功能区插座的数量都为2 各功能区大功率电器数量都为1 那么根据公式：1.5MM线需要290米(3卷内), 2.5MM需要690米(7卷多)，4MM需要381米(4卷)，电话线,有线和网线都可以算出来了， 这个*应该是相当准确的，还留余地的。

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